13331243311341 has 8 divisors (see below), whose sum is σ = 17775271932384. Its totient is φ = 8887355115600.

The previous prime is 13331243311313. The next prime is 13331243311343. The reversal of 13331243311341 is 14311334213331.

13331243311341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13331243311341 - 2⁷ = 13331243311213 is a prime.

It is a super-3 number, since 3×13331243311341³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13331243311343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34884610 + ... + 35264691.

It is an arithmetic number, because the mean of its divisors is an integer number (2221908991548).

Almost surely, 2^{13331243311341} is an apocalyptic number.

It is an amenable number.

13331243311341 is a deficient number, since it is larger than the sum of its proper divisors (4444028621043).

13331243311341 is an equidigital number, since it uses as much as digits as its factorization.

13331243311341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70212651.

The product of its digits is 23328, while the sum is 33.

Adding to 13331243311341 its reverse (14311334213331), we get a palindrome (27642577524672).

The spelling of 13331243311341 in words is "thirteen trillion, three hundred thirty-one billion, two hundred forty-three million, three hundred eleven thousand, three hundred forty-one".