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133313121132300 = 223352173788189101
BaseRepresentation
bin11110010011111101100001…
…001110101001111100001100
3122111000121110121221011201000
4132103331201032221330030
5114433200233002213200
61151311111414020300
740036361263524234
oct3623754116517414
9574017417834630
10133313121132300
113952886046009a
1212b50b86647690
1359504b1417aa5
1424cc564a94cc4
151062ba8379300
hex793f613a9f0c

133313121132300 has 576 divisors, whose sum is σ = 466586172823680. Its totient is φ = 32517365760000.

The previous prime is 133313121132227. The next prime is 133313121132329. The reversal of 133313121132300 is 3231121313331.

133313121132300 is a `hidden beast` number, since 1 + 3 + 3 + 3 + 1 + 312 + 11 + 32 + 300 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 1496157750 + ... + 1496246850.

It is an arithmetic number, because the mean of its divisors is an integer number (810045438930).

Almost surely, 2133313121132300 is an apocalyptic number.

133313121132300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133313121132300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (233293086411840).

133313121132300 is an abundant number, since it is smaller than the sum of its proper divisors (333273051691380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133313121132300 is a wasteful number, since it uses less digits than its factorization.

133313121132300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 90059 (or 90046 counting only the distinct ones).

The product of its (nonzero) digits is 2916, while the sum is 27.

Adding to 133313121132300 its reverse (3231121313331), we get a palindrome (136544242445631).

The spelling of 133313121132300 in words is "one hundred thirty-three trillion, three hundred thirteen billion, one hundred twenty-one million, one hundred thirty-two thousand, three hundred".