Base | Representation |
---|---|
bin | 111110000101000010… |
… | …1001100111101001111 |
3 | 110202002211011021202202 |
4 | 1330022011030331033 |
5 | 4141011124402002 |
6 | 141124310512115 |
7 | 12426423561353 |
oct | 1741205147517 |
9 | 422084137682 |
10 | 133313122127 |
11 | 515a0866899 |
12 | 21a0636563b |
13 | c7573cc823 |
14 | 66494dd463 |
15 | 3703b59502 |
hex | 1f0a14cf4f |
133313122127 has 2 divisors, whose sum is σ = 133313122128. Its totient is φ = 133313122126.
The previous prime is 133313122091. The next prime is 133313122141. The reversal of 133313122127 is 721221313331.
It is a strong prime.
It is an emirp because it is prime and its reverse (721221313331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133313122127 - 212 = 133313118031 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133313122127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133313122427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66656561063 + 66656561064.
It is an arithmetic number, because the mean of its divisors is an integer number (66656561064).
Almost surely, 2133313122127 is an apocalyptic number.
133313122127 is a deficient number, since it is larger than the sum of its proper divisors (1).
133313122127 is an equidigital number, since it uses as much as digits as its factorization.
133313122127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4536, while the sum is 29.
Adding to 133313122127 its reverse (721221313331), we get a palindrome (854534435458).
The spelling of 133313122127 in words is "one hundred thirty-three billion, three hundred thirteen million, one hundred twenty-two thousand, one hundred twenty-seven".
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