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1333131739957 is a prime number
BaseRepresentation
bin10011011001100100110…
…110000000001100110101
311201110001020120020012001
4103121210312000030311
5133320223211134312
62500233211455301
7165213150551413
oct23314466001465
94643036506161
101333131739957
11474418126866
12196453157531
139893824b4b4
14487498d02b3
1524a27967057
hex13664d80335

1333131739957 has 2 divisors, whose sum is σ = 1333131739958. Its totient is φ = 1333131739956.

The previous prime is 1333131739943. The next prime is 1333131739963. The reversal of 1333131739957 is 7599371313331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1209502851076 + 123628888881 = 1099774^2 + 351609^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1333131739957 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1333131739898 and 1333131739907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1333131739937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666565869978 + 666565869979.

It is an arithmetic number, because the mean of its divisors is an integer number (666565869979).

Almost surely, 21333131739957 is an apocalyptic number.

It is an amenable number.

1333131739957 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333131739957 is an equidigital number, since it uses as much as digits as its factorization.

1333131739957 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4822335, while the sum is 55.

The spelling of 1333131739957 in words is "one trillion, three hundred thirty-three billion, one hundred thirty-one million, seven hundred thirty-nine thousand, nine hundred fifty-seven".