Base | Representation |
---|---|
bin | 1100000111111111010101… |
… | …0111010000010000101011 |
3 | 1202012110200012010112001202 |
4 | 3001333311113100100223 |
5 | 3221410201402031243 |
6 | 44204205521234415 |
7 | 2544106343404511 |
oct | 301776527202053 |
9 | 52173605115052 |
10 | 13331400033323 |
11 | 427a8a6851859 |
12 | 15b386aa92a0b |
13 | 7591b7c3caa8 |
14 | 3413594d24b1 |
15 | 181ba881e4b8 |
hex | c1ff55d042b |
13331400033323 has 4 divisors (see below), whose sum is σ = 13331612965800. Its totient is φ = 13331187100848.
The previous prime is 13331400033317. The next prime is 13331400033349. The reversal of 13331400033323 is 32333000413331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13331400033323 - 24 = 13331400033307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13331400033313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106372298 + ... + 106497551.
It is an arithmetic number, because the mean of its divisors is an integer number (3332903241450).
Almost surely, 213331400033323 is an apocalyptic number.
13331400033323 is a deficient number, since it is larger than the sum of its proper divisors (212932477).
13331400033323 is an equidigital number, since it uses as much as digits as its factorization.
13331400033323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 212932476.
The product of its (nonzero) digits is 17496, while the sum is 29.
Adding to 13331400033323 its reverse (32333000413331), we get a palindrome (45664400446654).
The spelling of 13331400033323 in words is "thirteen trillion, three hundred thirty-one billion, four hundred million, thirty-three thousand, three hundred twenty-three".
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