133314311441 has 2 divisors, whose sum is σ = 133314311442. Its totient is φ = 133314311440.

The previous prime is 133314311399. The next prime is 133314311443. The reversal of 133314311441 is 144113413331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107893197841 + 25421113600 = 328471^2 + 159440^2 .

It is a cyclic number.

It is not a de Polignac number, because 133314311441 - 2¹⁰ = 133314310417 is a prime.

Together with 133314311443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133314311443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66657155720 + 66657155721.

It is an arithmetic number, because the mean of its divisors is an integer number (66657155721).

Almost surely, 2^133314311441 is an apocalyptic number.

It is an amenable number.

133314311441 is a deficient number, since it is larger than the sum of its proper divisors (1).

133314311441 is an equidigital number, since it uses as much as digits as its factorization.

133314311441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 29.

Adding to 133314311441 its reverse (144113413331), we get a palindrome (277427724772).

The spelling of 133314311441 in words is "one hundred thirty-three billion, three hundred fourteen million, three hundred eleven thousand, four hundred forty-one".