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133314999457 is a prime number
BaseRepresentation
bin111110000101000110…
…0010111010010100001
3110202002221200122222111
41330022030113102201
54141012114440312
6141124415035321
712426445540543
oct1741214272241
9422087618874
10133314999457
11515a1929302
1221a06b0bb41
13c757909183
14664986b693
153703dca8a7
hex1f0a3174a1

133314999457 has 2 divisors, whose sum is σ = 133314999458. Its totient is φ = 133314999456.

The previous prime is 133314999371. The next prime is 133314999469. The reversal of 133314999457 is 754999413331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89802708241 + 43512291216 = 299671^2 + 208596^2 .

It is a cyclic number.

It is not a de Polignac number, because 133314999457 - 223 = 133306610849 is a prime.

It is not a weakly prime, because it can be changed into another prime (133314996457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66657499728 + 66657499729.

It is an arithmetic number, because the mean of its divisors is an integer number (66657499729).

Almost surely, 2133314999457 is an apocalyptic number.

It is an amenable number.

133314999457 is a deficient number, since it is larger than the sum of its proper divisors (1).

133314999457 is an equidigital number, since it uses as much as digits as its factorization.

133314999457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11022480, while the sum is 58.

The spelling of 133314999457 in words is "one hundred thirty-three billion, three hundred fourteen million, nine hundred ninety-nine thousand, four hundred fifty-seven".