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133315705032703 is a prime number
BaseRepresentation
bin11110010011111111111011…
…001111011100111111111111
3122111000212010200222220200221
4132103333323033130333333
5114433221030442021303
61151312220040002211
740036512310362454
oct3623777317347777
9574025120886627
10133315705032703
1139529966a59776
1212b51587a60367
135950803841a3b
1424cc72bd0582b
151062caa1294bd
hex793ffb3dcfff

133315705032703 has 2 divisors, whose sum is σ = 133315705032704. Its totient is φ = 133315705032702.

The previous prime is 133315705032691. The next prime is 133315705032709. The reversal of 133315705032703 is 307230507513331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133315705032703 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133315705032703.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133315705032709) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (37) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66657852516351 + 66657852516352.

It is an arithmetic number, because the mean of its divisors is an integer number (66657852516352).

Almost surely, 2133315705032703 is an apocalyptic number.

133315705032703 is a deficient number, since it is larger than the sum of its proper divisors (1).

133315705032703 is an equidigital number, since it uses as much as digits as its factorization.

133315705032703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 595350, while the sum is 43.

The spelling of 133315705032703 in words is "one hundred thirty-three trillion, three hundred fifteen billion, seven hundred five million, thirty-two thousand, seven hundred three".