Base | Representation |
---|---|
bin | 111110000101001111… |
… | …1011111100010111110 |
3 | 110202010022010102122211 |
4 | 1330022133133202332 |
5 | 4141014410422024 |
6 | 141125114331034 |
7 | 12426536264335 |
oct | 1741237374276 |
9 | 422108112584 |
10 | 133320014014 |
11 | 515a4743870 |
12 | 21a08729a7a |
13 | c758973775 |
14 | 664a3b4d1c |
15 | 370456b594 |
hex | 1f0a7df8be |
133320014014 has 32 divisors (see below), whose sum is σ = 224120359296. Its totient is φ = 58945295520.
The previous prime is 133320014011. The next prime is 133320014057. The reversal of 133320014014 is 410410023331.
133320014014 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1333200140142 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133320014011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3074109 + ... + 3117175.
It is an arithmetic number, because the mean of its divisors is an integer number (7003761228).
Almost surely, 2133320014014 is an apocalyptic number.
133320014014 is a deficient number, since it is larger than the sum of its proper divisors (90800345282).
133320014014 is a wasteful number, since it uses less digits than its factorization.
133320014014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46920.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 133320014014 its reverse (410410023331), we get a palindrome (543730037345).
The spelling of 133320014014 in words is "one hundred thirty-three billion, three hundred twenty million, fourteen thousand, fourteen".
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