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13332022101133 is a prime number
BaseRepresentation
bin1100001000000001101001…
…1100010000010010001101
31202012112021112122211200021
43002000122130100102031
53221412440124214013
644204351342302141
72544130636034341
oct302003234202215
952175245584607
1013332022101133
114280095a0258a
1215b3a03287951
13759286a94058
143413b7d81621
15181be324aa8d
hexc201a71048d

13332022101133 has 2 divisors, whose sum is σ = 13332022101134. Its totient is φ = 13332022101132.

The previous prime is 13332022101127. The next prime is 13332022101137. The reversal of 13332022101133 is 33110122023331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11964252087844 + 1367770013289 = 3458938^2 + 1169517^2 .

It is a cyclic number.

It is not a de Polignac number, because 13332022101133 - 217 = 13332021970061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13332022101098 and 13332022101107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13332022101137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666011050566 + 6666011050567.

It is an arithmetic number, because the mean of its divisors is an integer number (6666011050567).

Almost surely, 213332022101133 is an apocalyptic number.

It is an amenable number.

13332022101133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332022101133 is an equidigital number, since it uses as much as digits as its factorization.

13332022101133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13332022101133 its reverse (33110122023331), we get a palindrome (46442144124464).

The spelling of 13332022101133 in words is "thirteen trillion, three hundred thirty-two billion, twenty-two million, one hundred one thousand, one hundred thirty-three".