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13332102121313 is a prime number
BaseRepresentation
bin1100001000000001111100…
…1101100000011101100001
31202012112111010020021201122
43002000133031200131201
53221413121120340223
644204403321342025
72544132630143333
oct302003715403541
952175433207648
1013332102121313
114280127097968
1215b3a26037915
1375929a530681
143413c4851453
15181bea2a55c8
hexc201f360761

13332102121313 has 2 divisors, whose sum is σ = 13332102121314. Its totient is φ = 13332102121312.

The previous prime is 13332102121159. The next prime is 13332102121321. The reversal of 13332102121313 is 31312120123331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6800949426769 + 6531152694544 = 2607863^2 + 2555612^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13332102121313 is a prime.

It is a super-3 number, since 3×133321021213133 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13332102121343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666051060656 + 6666051060657.

It is an arithmetic number, because the mean of its divisors is an integer number (6666051060657).

Almost surely, 213332102121313 is an apocalyptic number.

It is an amenable number.

13332102121313 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332102121313 is an equidigital number, since it uses as much as digits as its factorization.

13332102121313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 26.

Adding to 13332102121313 its reverse (31312120123331), we get a palindrome (44644222244644).

The spelling of 13332102121313 in words is "thirteen trillion, three hundred thirty-two billion, one hundred two million, one hundred twenty-one thousand, three hundred thirteen".