Base | Representation |
---|---|
bin | 1100001000000001111100… |
… | …1101100000011011000111 |
3 | 1202012112111010020021111221 |
4 | 3002000133031200123013 |
5 | 3221413121120334114 |
6 | 44204403321341211 |
7 | 2544132630143023 |
oct | 302003715403307 |
9 | 52175433207457 |
10 | 13332102121159 |
11 | 4280127097838 |
12 | 15b3a26037807 |
13 | 75929a530593 |
14 | 3413c4851383 |
15 | 181bea2a5524 |
hex | c201f3606c7 |
13332102121159 has 2 divisors, whose sum is σ = 13332102121160. Its totient is φ = 13332102121158.
The previous prime is 13332102121081. The next prime is 13332102121313. The reversal of 13332102121159 is 95112120123331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13332102121159 - 235 = 13297742382791 is a prime.
It is a super-3 number, since 3×133321021211593 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13332102101159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666051060579 + 6666051060580.
It is an arithmetic number, because the mean of its divisors is an integer number (6666051060580).
Almost surely, 213332102121159 is an apocalyptic number.
13332102121159 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332102121159 is an equidigital number, since it uses as much as digits as its factorization.
13332102121159 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 34.
The spelling of 13332102121159 in words is "thirteen trillion, three hundred thirty-two billion, one hundred two million, one hundred twenty-one thousand, one hundred fifty-nine".
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