13332222144013 has 4 divisors (see below), whose sum is σ = 13334510157760. Its totient is φ = 13329934130268.

The previous prime is 13332222143963. The next prime is 13332222144047. The reversal of 13332222144013 is 31044122223331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13332222144013 - 2¹³ = 13332222135821 is a prime.

It is a super-3 number, since 3×13332222144013³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13332222142013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1143998133 + ... + 1144009786.

It is an arithmetic number, because the mean of its divisors is an integer number (3333627539440).

Almost surely, 2^{13332222144013} is an apocalyptic number.

It is an amenable number.

13332222144013 is a deficient number, since it is larger than the sum of its proper divisors (2288013747).

13332222144013 is an equidigital number, since it uses as much as digits as its factorization.

13332222144013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2288013746.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13332222144013 its reverse (31044122223331), we get a palindrome (44376344367344).

The spelling of 13332222144013 in words is "thirteen trillion, three hundred thirty-two billion, two hundred twenty-two million, one hundred forty-four thousand, thirteen".