Base | Representation |
---|---|
bin | 11110010100000101111111… |
… | …110111001111010100000011 |
3 | 122111001110222002111200212211 |
4 | 132110011333313033110003 |
5 | 114433322404101202321 |
6 | 1151315215030002551 |
7 | 40040133010361311 |
oct | 3624057767172403 |
9 | 574043862450784 |
10 | 133322225022211 |
11 | 3953170235a355 |
12 | 12b528a74a6457 |
13 | 59513025712b4 |
14 | 24ccb89bd10b1 |
15 | 106303c7280e1 |
hex | 79417fdcf503 |
133322225022211 has 2 divisors, whose sum is σ = 133322225022212. Its totient is φ = 133322225022210.
The previous prime is 133322225022209. The next prime is 133322225022241. The reversal of 133322225022211 is 112220522223331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133322225022211 - 21 = 133322225022209 is a prime.
It is a super-3 number, since 3×1333222250222113 (a number of 43 digits) contains 333 as substring.
Together with 133322225022209, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (133322225022241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66661112511105 + 66661112511106.
It is an arithmetic number, because the mean of its divisors is an integer number (66661112511106).
Almost surely, 2133322225022211 is an apocalyptic number.
133322225022211 is a deficient number, since it is larger than the sum of its proper divisors (1).
133322225022211 is an equidigital number, since it uses as much as digits as its factorization.
133322225022211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 133322225022211 its reverse (112220522223331), we get a palindrome (245542747245542).
The spelling of 133322225022211 in words is "one hundred thirty-three trillion, three hundred twenty-two billion, two hundred twenty-five million, twenty-two thousand, two hundred eleven".
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