Base | Representation |
---|---|
bin | 11110010100000110111010… |
… | …001101110100101110010111 |
3 | 122111001120111022122222221112 |
4 | 132110012322031310232113 |
5 | 114433331410212134033 |
6 | 1151315500121205235 |
7 | 40040166165623513 |
oct | 3624067215645627 |
9 | 574046438588845 |
10 | 133323204021143 |
11 | 39532064a39784 |
12 | 12b52b1b33081b |
13 | 595142a3374c6 |
14 | 24ccc3dc33143 |
15 | 106309865bc48 |
hex | 7941ba374b97 |
133323204021143 has 2 divisors, whose sum is σ = 133323204021144. Its totient is φ = 133323204021142.
The previous prime is 133323204021067. The next prime is 133323204021149. The reversal of 133323204021143 is 341120402323331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133323204021143 - 218 = 133323203758999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133323204021149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66661602010571 + 66661602010572.
It is an arithmetic number, because the mean of its divisors is an integer number (66661602010572).
Almost surely, 2133323204021143 is an apocalyptic number.
133323204021143 is a deficient number, since it is larger than the sum of its proper divisors (1).
133323204021143 is an equidigital number, since it uses as much as digits as its factorization.
133323204021143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 133323204021143 its reverse (341120402323331), we get a palindrome (474443606344474).
The spelling of 133323204021143 in words is "one hundred thirty-three trillion, three hundred twenty-three billion, two hundred four million, twenty-one thousand, one hundred forty-three".
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