133323240000047 has 2 divisors, whose sum is σ = 133323240000048. Its totient is φ = 133323240000046.

The previous prime is 133323240000011. The next prime is 133323240000061. The reversal of 133323240000047 is 740000042323331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133323240000047 - 2²⁴ = 133323223222831 is a prime.

It is a super-2 number, since 2×133323240000047² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133323239999968 and 133323240000022.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133323240200047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66661620000023 + 66661620000024.

It is an arithmetic number, because the mean of its divisors is an integer number (66661620000024).

Almost surely, 2^{133323240000047} is an apocalyptic number.

133323240000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

133323240000047 is an equidigital number, since it uses as much as digits as its factorization.

133323240000047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 32.

Adding to 133323240000047 its reverse (740000042323331), we get a palindrome (873323282323378).

The spelling of 133323240000047 in words is "one hundred thirty-three trillion, three hundred twenty-three billion, two hundred forty million, forty-seven", and thus it is an aban number.