Base | Representation |
---|---|
bin | 1100001000000010110001… |
… | …1101000100010111010011 |
3 | 1202012120001121022100112121 |
4 | 3002000230131010113103 |
5 | 3221414100010214324 |
6 | 44204441335435111 |
7 | 2544141265521265 |
oct | 302005435042723 |
9 | 52176047270477 |
10 | 13332324304339 |
11 | 42802305512a7 |
12 | 15b3a88525a97 |
13 | 759304583911 |
14 | 341406169b35 |
15 | 181c0ea425e4 |
hex | c202c7445d3 |
13332324304339 has 2 divisors, whose sum is σ = 13332324304340. Its totient is φ = 13332324304338.
The previous prime is 13332324304337. The next prime is 13332324304379. The reversal of 13332324304339 is 93340342323331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13332324304339 - 21 = 13332324304337 is a prime.
Together with 13332324304337, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13332324304295 and 13332324304304.
It is not a weakly prime, because it can be changed into another prime (13332324304337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666162152169 + 6666162152170.
It is an arithmetic number, because the mean of its divisors is an integer number (6666162152170).
Almost surely, 213332324304339 is an apocalyptic number.
13332324304339 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332324304339 is an equidigital number, since it uses as much as digits as its factorization.
13332324304339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1259712, while the sum is 43.
The spelling of 13332324304339 in words is "thirteen trillion, three hundred thirty-two billion, three hundred twenty-four million, three hundred four thousand, three hundred thirty-nine".
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