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13332404242440 = 233651239136899
BaseRepresentation
bin1100001000000011000100…
…1110000000100000001000
31202012120021011201122000000
43002000301032000200020
53221414230441224230
644204453313043000
72544143256136053
oct302006116004010
952176234648000
1013332404242440
11428027168aa48
1215b3aab256460
13759317cc1a7a
14341412a17a9a
15181c16a82b60
hexc2031380808

13332404242440 has 224 divisors, whose sum is σ = 44981138376000. Its totient is φ = 3554924526720.

The previous prime is 13332404242427. The next prime is 13332404242447. The reversal of 13332404242440 is 4424240423331.

13332404242440 is a `hidden beast` number, since 1 + 3 + 3 + 3 + 2 + 404 + 2 + 4 + 244 + 0 = 666.

It is a super-2 number, since 2×133324042424402 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 13332404242395 and 13332404242404.

It is not an unprimeable number, because it can be changed into a prime (13332404242447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 361303111 + ... + 361340009.

Almost surely, 213332404242440 is an apocalyptic number.

13332404242440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13332404242440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22490569188000).

13332404242440 is an abundant number, since it is smaller than the sum of its proper divisors (31648734133560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13332404242440 is a wasteful number, since it uses less digits than its factorization.

13332404242440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49319 (or 49300 counting only the distinct ones).

The product of its (nonzero) digits is 221184, while the sum is 36.

Adding to 13332404242440 its reverse (4424240423331), we get a palindrome (17756644665771).

The spelling of 13332404242440 in words is "thirteen trillion, three hundred thirty-two billion, four hundred four million, two hundred forty-two thousand, four hundred forty".