13332515465141 has 4 divisors (see below), whose sum is σ = 13333057616172. Its totient is φ = 13331973314112.

The previous prime is 13332515465119. The next prime is 13332515465279. The reversal of 13332515465141 is 14156451523331.

13332515465141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1173723058225 + 12158792406916 = 1083385^2 + 3486946^2 .

It is a cyclic number.

It is not a de Polignac number, because 13332515465141 - 2¹⁸ = 13332515202997 is a prime.

It is a super-2 number, since 2×13332515465141² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13332515465092 and 13332515465101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13332515465441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 271038626 + ... + 271087811.

It is an arithmetic number, because the mean of its divisors is an integer number (3333264404043).

Almost surely, 2^{13332515465141} is an apocalyptic number.

It is an amenable number.

13332515465141 is a deficient number, since it is larger than the sum of its proper divisors (542151031).

13332515465141 is an equidigital number, since it uses as much as digits as its factorization.

13332515465141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 542151030.

The product of its digits is 648000, while the sum is 44.

Adding to 13332515465141 its reverse (14156451523331), we get a palindrome (27488966988472).

The spelling of 13332515465141 in words is "thirteen trillion, three hundred thirty-two billion, five hundred fifteen million, four hundred sixty-five thousand, one hundred forty-one".