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133328440793 is a prime number
BaseRepresentation
bin111110000101011111…
…1101000110111011001
3110202010212222120000202
41330022333220313121
54141024040101133
6141130015111545
712430001022242
oct1741277506731
9422125876022
10133328440793
11515a9479a49
1221a0b5125b5
13c75a634222
14664b569cc9
1537051832e8
hex1f0afe8dd9

133328440793 has 2 divisors, whose sum is σ = 133328440794. Its totient is φ = 133328440792.

The previous prime is 133328440787. The next prime is 133328440811. The reversal of 133328440793 is 397044823331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102407680144 + 30920760649 = 320012^2 + 175843^2 .

It is a cyclic number.

It is not a de Polignac number, because 133328440793 - 214 = 133328424409 is a prime.

It is a super-3 number, since 3×1333284407933 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (133328440393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66664220396 + 66664220397.

It is an arithmetic number, because the mean of its divisors is an integer number (66664220397).

Almost surely, 2133328440793 is an apocalyptic number.

It is an amenable number.

133328440793 is a deficient number, since it is larger than the sum of its proper divisors (1).

133328440793 is an equidigital number, since it uses as much as digits as its factorization.

133328440793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 47.

The spelling of 133328440793 in words is "one hundred thirty-three billion, three hundred twenty-eight million, four hundred forty thousand, seven hundred ninety-three".