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133330002019 is a prime number
BaseRepresentation
bin111110000101100010…
…1100110000001100011
3110202010222220212121221
41330023011212001203
54141024440031034
6141130112355511
712430020214024
oct1741305460143
9422128825557
10133330002019
11515aa345a15
1221a0bb45b97
13c75aa5ca26
14664b854c4b
153705390bb4
hex1f0b166063

133330002019 has 2 divisors, whose sum is σ = 133330002020. Its totient is φ = 133330002018.

The previous prime is 133330001983. The next prime is 133330002023. The reversal of 133330002019 is 910200033331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133330002019 - 219 = 133329477731 is a prime.

It is a super-2 number, since 2×1333300020192 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133330001984 and 133330002002.

It is not a weakly prime, because it can be changed into another prime (133330002059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66665001009 + 66665001010.

It is an arithmetic number, because the mean of its divisors is an integer number (66665001010).

Almost surely, 2133330002019 is an apocalyptic number.

133330002019 is a deficient number, since it is larger than the sum of its proper divisors (1).

133330002019 is an equidigital number, since it uses as much as digits as its factorization.

133330002019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 25.

The spelling of 133330002019 in words is "one hundred thirty-three billion, three hundred thirty million, two thousand, nineteen".