Base | Representation |
---|---|
bin | 111110000101100110… |
… | …1101001011100110111 |
3 | 110202011010220010122002 |
4 | 1330023031221130313 |
5 | 4141031010110312 |
6 | 141130225525515 |
7 | 12430044156056 |
oct | 1741315513467 |
9 | 422133803562 |
10 | 133332113207 |
11 | 516005580a7 |
12 | 21a107a389b |
13 | c75b31b957 |
14 | 664bc4439d |
15 | 370565b4c2 |
hex | 1f0b369737 |
133332113207 has 2 divisors, whose sum is σ = 133332113208. Its totient is φ = 133332113206.
The previous prime is 133332113191. The next prime is 133332113263. The reversal of 133332113207 is 702311233331.
It is a weak prime.
It is an emirp because it is prime and its reverse (702311233331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133332113207 - 24 = 133332113191 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133332113207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133332113267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666056603 + 66666056604.
It is an arithmetic number, because the mean of its divisors is an integer number (66666056604).
Almost surely, 2133332113207 is an apocalyptic number.
133332113207 is a deficient number, since it is larger than the sum of its proper divisors (1).
133332113207 is an equidigital number, since it uses as much as digits as its factorization.
133332113207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 29.
Adding to 133332113207 its reverse (702311233331), we get a palindrome (835643346538).
The spelling of 133332113207 in words is "one hundred thirty-three billion, three hundred thirty-two million, one hundred thirteen thousand, two hundred seven".
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