Base | Representation |
---|---|
bin | 11110010100001111001101… |
… | …101010011000101010110111 |
3 | 122111002102111201001022211021 |
4 | 132110033031222120222313 |
5 | 114434003140233210403 |
6 | 1151323532550122011 |
7 | 40040633143156513 |
oct | 3624171552305267 |
9 | 574072451038737 |
10 | 133332120210103 |
11 | 3953591a996491 |
12 | 12b547a9350307 |
13 | 595221b621869 |
14 | 24cd44806d143 |
15 | 106341b2d08bd |
hex | 7943cda98ab7 |
133332120210103 has 2 divisors, whose sum is σ = 133332120210104. Its totient is φ = 133332120210102.
The previous prime is 133332120209971. The next prime is 133332120210137. The reversal of 133332120210103 is 301012021233331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133332120210103 - 217 = 133332120079031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133332120210503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666060105051 + 66666060105052.
It is an arithmetic number, because the mean of its divisors is an integer number (66666060105052).
Almost surely, 2133332120210103 is an apocalyptic number.
133332120210103 is a deficient number, since it is larger than the sum of its proper divisors (1).
133332120210103 is an equidigital number, since it uses as much as digits as its factorization.
133332120210103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 133332120210103 its reverse (301012021233331), we get a palindrome (434344141443434).
The spelling of 133332120210103 in words is "one hundred thirty-three trillion, three hundred thirty-two billion, one hundred twenty million, two hundred ten thousand, one hundred three".
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