Base | Representation |
---|---|
bin | 1100001000000110000111… |
… | …0111000110001101111011 |
3 | 1202012122101001022200010101 |
4 | 3002001201313012031323 |
5 | 3221422413400220443 |
6 | 44205110304300231 |
7 | 2544202425524224 |
oct | 302014167061573 |
9 | 52178331280111 |
10 | 13333220320123 |
11 | 4280650302210 |
12 | 15b4098611677 |
13 | 7594180b3982 |
14 | 34148d16a24b |
15 | 181c6353384d |
hex | c2061dc637b |
13333220320123 has 4 divisors (see below), whose sum is σ = 14545331258328. Its totient is φ = 12121109381920.
The previous prime is 13333220320073. The next prime is 13333220320177. The reversal of 13333220320123 is 32102302233331.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-13333220320123 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13333220320091 and 13333220320100.
It is not an unprimeable number, because it can be changed into a prime (13333220320183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 606055469086 + ... + 606055469107.
It is an arithmetic number, because the mean of its divisors is an integer number (3636332814582).
Almost surely, 213333220320123 is an apocalyptic number.
13333220320123 is a deficient number, since it is larger than the sum of its proper divisors (1212110938205).
13333220320123 is a wasteful number, since it uses less digits than its factorization.
13333220320123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1212110938204.
The product of its (nonzero) digits is 11664, while the sum is 28.
Adding to 13333220320123 its reverse (32102302233331), we get a palindrome (45435522553454).
The spelling of 13333220320123 in words is "thirteen trillion, three hundred thirty-three billion, two hundred twenty million, three hundred twenty thousand, one hundred twenty-three".
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