Base | Representation |
---|---|
bin | 1100001000000110100010… |
… | …0101010111010100110111 |
3 | 1202012122122220120002122201 |
4 | 3002001220211113110313 |
5 | 3221423131234041434 |
6 | 44205125414005331 |
7 | 2544205265324656 |
oct | 302015045272467 |
9 | 52178586502581 |
10 | 13333333112119 |
11 | 42806a8a40539 |
12 | 15b410a346847 |
13 | 759435585ab7 |
14 | 3414a012b19d |
15 | 181c6d3b3614 |
hex | c2068957537 |
13333333112119 has 2 divisors, whose sum is σ = 13333333112120. Its totient is φ = 13333333112118.
The previous prime is 13333333112083. The next prime is 13333333112147. The reversal of 13333333112119 is 91121133333331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13333333112119 - 213 = 13333333103927 is a prime.
It is a super-2 number, since 2×133333331121192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13333333112159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666666556059 + 6666666556060.
It is an arithmetic number, because the mean of its divisors is an integer number (6666666556060).
Almost surely, 213333333112119 is an apocalyptic number.
13333333112119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13333333112119 is an equidigital number, since it uses as much as digits as its factorization.
13333333112119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 39366, while the sum is 37.
The spelling of 13333333112119 in words is "thirteen trillion, three hundred thirty-three billion, three hundred thirty-three million, one hundred twelve thousand, one hundred nineteen".
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