Base | Representation |
---|---|
bin | 11110010100010000010101… |
… | …111110000101010001111101 |
3 | 122111002112122020202100202021 |
4 | 132110100111332011101331 |
5 | 114434013131313124432 |
6 | 1151324253203400141 |
7 | 40041005203432351 |
oct | 3624202576052175 |
9 | 574075566670667 |
10 | 133333333333117 |
11 | 39536392745795 |
12 | 12b54a87683051 |
13 | 5952382a5c228 |
14 | 24cd521217461 |
15 | 106348ca5e697 |
hex | 794415f8547d |
133333333333117 has 2 divisors, whose sum is σ = 133333333333118. Its totient is φ = 133333333333116.
The previous prime is 133333333333091. The next prime is 133333333333139. The reversal of 133333333333117 is 711333333333331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67632679240281 + 65700654092836 = 8223909^2 + 8105594^2 .
It is a cyclic number.
It is not a de Polignac number, because 133333333333117 - 211 = 133333333331069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133333333333177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666666666558 + 66666666666559.
It is an arithmetic number, because the mean of its divisors is an integer number (66666666666559).
Almost surely, 2133333333333117 is an apocalyptic number.
It is an amenable number.
133333333333117 is a deficient number, since it is larger than the sum of its proper divisors (1).
133333333333117 is an equidigital number, since it uses as much as digits as its factorization.
133333333333117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1240029, while the sum is 43.
Adding to 133333333333117 its reverse (711333333333331), we get a palindrome (844666666666448).
The spelling of 133333333333117 in words is "one hundred thirty-three trillion, three hundred thirty-three billion, three hundred thirty-three million, three hundred thirty-three thousand, one hundred seventeen".
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