Base | Representation |
---|---|
bin | 1100001000000110100010… |
… | …1101110101100011101111 |
3 | 1202012122200001201221021101 |
4 | 3002001220231311203233 |
5 | 3221423132321124403 |
6 | 44205125533343531 |
7 | 2544205323235102 |
oct | 302015055654357 |
9 | 52178601657241 |
10 | 13333335333103 |
11 | 42806aa218165 |
12 | 15b410b037ba7 |
13 | 759435b829a6 |
14 | 3414a0548739 |
15 | 181c6d6a171d |
hex | c2068b758ef |
13333335333103 has 2 divisors, whose sum is σ = 13333335333104. Its totient is φ = 13333335333102.
The previous prime is 13333335333083. The next prime is 13333335333107. The reversal of 13333335333103 is 30133353333331.
13333335333103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13333335333103 - 221 = 13333333235951 is a prime.
It is a super-2 number, since 2×133333353331032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13333335333107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666667666551 + 6666667666552.
It is an arithmetic number, because the mean of its divisors is an integer number (6666667666552).
Almost surely, 213333335333103 is an apocalyptic number.
13333335333103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13333335333103 is an equidigital number, since it uses as much as digits as its factorization.
13333335333103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 295245, while the sum is 37.
Adding to 13333335333103 its reverse (30133353333331), we get a palindrome (43466688666434).
The spelling of 13333335333103 in words is "thirteen trillion, three hundred thirty-three billion, three hundred thirty-five million, three hundred thirty-three thousand, one hundred three".
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