133340000043331 has 4 divisors (see below), whose sum is σ = 134660198063664. Its totient is φ = 132019802023000.

The previous prime is 133340000043311. The next prime is 133340000043361.

133340000043331 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133340000043331 - 2⁹ = 133340000042819 is a prime.

It is a super-2 number, since 2×133340000043331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 133340000043331.

It is not an unprimeable number, because it can be changed into a prime (133340000043311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 660099010015 + ... + 660099010216.

It is an arithmetic number, because the mean of its divisors is an integer number (33665049515916).

Almost surely, 2^{133340000043331} is an apocalyptic number.

133340000043331 is a deficient number, since it is larger than the sum of its proper divisors (1320198020333).

133340000043331 is a wasteful number, since it uses less digits than its factorization.

133340000043331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1320198020332.

The product of its (nonzero) digits is 11664, while the sum is 28.

It can be divided in two parts, 1333400000 and 43331, that added together give a palindrome (1333443331).

The spelling of 133340000043331 in words is "one hundred thirty-three trillion, three hundred forty billion, forty-three thousand, three hundred thirty-one".