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133343300165083 is a prime number
BaseRepresentation
bin11110010100011001101000…
…000010100001110111011011
3122111010111100212002212212221
4132110121220002201313123
5114434144034320240313
61151333022203244511
740041510166212451
oct3624315002416733
9574114325085787
10133343300165083
113953a6377660a8
1212b569a9519737
1359532b0905738
1424cdbc8bc49d1
151063872a69c8d
hex7946680a1ddb

133343300165083 has 2 divisors, whose sum is σ = 133343300165084. Its totient is φ = 133343300165082.

The previous prime is 133343300165029. The next prime is 133343300165099. The reversal of 133343300165083 is 380561003343331.

It is a strong prime.

It is an emirp because it is prime and its reverse (380561003343331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133343300165083 - 229 = 133342763294171 is a prime.

It is not a weakly prime, because it can be changed into another prime (133343300165183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66671650082541 + 66671650082542.

It is an arithmetic number, because the mean of its divisors is an integer number (66671650082542).

Almost surely, 2133343300165083 is an apocalyptic number.

133343300165083 is a deficient number, since it is larger than the sum of its proper divisors (1).

133343300165083 is an equidigital number, since it uses as much as digits as its factorization.

133343300165083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 699840, while the sum is 43.

The spelling of 133343300165083 in words is "one hundred thirty-three trillion, three hundred forty-three billion, three hundred million, one hundred sixty-five thousand, eighty-three".