Base | Representation |
---|---|
bin | 1100001000001010010011… |
… | …0110111001011101111011 |
3 | 1202012202021101100212101222 |
4 | 3002002210312321131323 |
5 | 3221432214122410441 |
6 | 44205414020102255 |
7 | 2544242324535134 |
oct | 302024466713573 |
9 | 52182241325358 |
10 | 13334344341371 |
11 | 4281077833a99 |
12 | 15b4350b3498b |
13 | 759566c251c1 |
14 | 34155855cc8b |
15 | 181ccc061d4b |
hex | c20a4db977b |
13334344341371 has 2 divisors, whose sum is σ = 13334344341372. Its totient is φ = 13334344341370.
The previous prime is 13334344341301. The next prime is 13334344341379. The reversal of 13334344341371 is 17314344343331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13334344341371 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13334344341379) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6667172170685 + 6667172170686.
It is an arithmetic number, because the mean of its divisors is an integer number (6667172170686).
Almost surely, 213334344341371 is an apocalyptic number.
13334344341371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13334344341371 is an equidigital number, since it uses as much as digits as its factorization.
13334344341371 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1306368, while the sum is 44.
The spelling of 13334344341371 in words is "thirteen trillion, three hundred thirty-four billion, three hundred forty-four million, three hundred forty-one thousand, three hundred seventy-one".
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