Base | Representation |
---|---|
bin | 1100001000001010010011… |
… | …0110111001111101001011 |
3 | 1202012202021101100222011001 |
4 | 3002002210312321331023 |
5 | 3221432214122441441 |
6 | 44205414020115431 |
7 | 2544242324544022 |
oct | 302024466717513 |
9 | 52182241328131 |
10 | 13334344343371 |
11 | 4281077835547 |
12 | 15b4350b35b77 |
13 | 759566c2609c |
14 | 34155855d8b9 |
15 | 181ccc062731 |
hex | c20a4db9f4b |
13334344343371 has 2 divisors, whose sum is σ = 13334344343372. Its totient is φ = 13334344343370.
The previous prime is 13334344343303. The next prime is 13334344343393. The reversal of 13334344343371 is 17334344343331.
13334344343371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13334344343371 is a prime.
It is not a weakly prime, because it can be changed into another prime (13334344341371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6667172171685 + 6667172171686.
It is an arithmetic number, because the mean of its divisors is an integer number (6667172171686).
Almost surely, 213334344343371 is an apocalyptic number.
13334344343371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13334344343371 is an equidigital number, since it uses as much as digits as its factorization.
13334344343371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3919104, while the sum is 46.
The spelling of 13334344343371 in words is "thirteen trillion, three hundred thirty-four billion, three hundred forty-four million, three hundred forty-three thousand, three hundred seventy-one".
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