Base | Representation |
---|---|
bin | 11000110101100100… |
… | …11111010010010101 |
3 | 1021102021220220101012 |
4 | 30122302133102111 |
5 | 204302043013403 |
6 | 10043053142005 |
7 | 651303026654 |
oct | 143262372225 |
9 | 37367826335 |
10 | 13334344853 |
11 | 5722987715 |
12 | 270178a905 |
13 | 13467362ab |
14 | 906d1d19b |
15 | 530996ed8 |
hex | 31ac9f495 |
13334344853 has 4 divisors (see below), whose sum is σ = 13385046048. Its totient is φ = 13283643660.
The previous prime is 13334344847. The next prime is 13334344861. The reversal of 13334344853 is 35844343331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13334344853 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13334344853.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13334344813) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25350203 + ... + 25350728.
It is an arithmetic number, because the mean of its divisors is an integer number (3346261512).
Almost surely, 213334344853 is an apocalyptic number.
It is an amenable number.
13334344853 is a deficient number, since it is larger than the sum of its proper divisors (50701195).
13334344853 is an equidigital number, since it uses as much as digits as its factorization.
13334344853 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50701194.
The product of its digits is 622080, while the sum is 41.
The spelling of 13334344853 in words is "thirteen billion, three hundred thirty-four million, three hundred forty-four thousand, eight hundred fifty-three".
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