Search a number
-
+
13334413003042 = 28117821388013
BaseRepresentation
bin1100001000001010100011…
…1100110100100100100010
31202012202110011120020111211
43002002220330310210202
53221432334212044132
644205424511500334
72544244120256005
oct302025074644442
952182404506454
1013334413003042
11428110257057a
1215b436bb276aa
13759578215801
1434156371353c
15181cd30c6147
hexc20a8f34922

13334413003042 has 8 divisors (see below), whose sum is σ = 20004083692956. Its totient is φ = 6666385105392.

The previous prime is 13334413003013. The next prime is 13334413003099. The reversal of 13334413003042 is 24030031443331.

It can be written as a sum of positive squares in 2 ways, for example, as 13020702113241 + 313710889801 = 3608421^2 + 560099^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13334413002995 and 13334413003013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 410677773 + ... + 410710240.

Almost surely, 213334413003042 is an apocalyptic number.

13334413003042 is a deficient number, since it is larger than the sum of its proper divisors (6669670689914).

13334413003042 is an equidigital number, since it uses as much as digits as its factorization.

13334413003042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 821396132.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 13334413003042 its reverse (24030031443331), we get a palindrome (37364444446373).

The spelling of 13334413003042 in words is "thirteen trillion, three hundred thirty-four billion, four hundred thirteen million, three thousand, forty-two".

Divisors: 1 2 8117 16234 821388013 1642776026 6667206501521 13334413003042