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13335245500133 is a prime number
BaseRepresentation
bin1100001000001101101010…
…0100100010111011100101
31202012211121012001110211102
43002003122210202323211
53221441040322001013
644210043251045445
72544303546341144
oct302033244427345
952184535043742
1013335245500133
11428149a4879a7
1215b45628a0885
1375967b83613b
143416020db75b
15181d3121bd58
hexc20da922ee5

13335245500133 has 2 divisors, whose sum is σ = 13335245500134. Its totient is φ = 13335245500132.

The previous prime is 13335245500121. The next prime is 13335245500163. The reversal of 13335245500133 is 33100554253331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12925340803489 + 409904696644 = 3595183^2 + 640238^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13335245500133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13335245500163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6667622750066 + 6667622750067.

It is an arithmetic number, because the mean of its divisors is an integer number (6667622750067).

Almost surely, 213335245500133 is an apocalyptic number.

It is an amenable number.

13335245500133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13335245500133 is an equidigital number, since it uses as much as digits as its factorization.

13335245500133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243000, while the sum is 38.

Adding to 13335245500133 its reverse (33100554253331), we get a palindrome (46435799753464).

The spelling of 13335245500133 in words is "thirteen trillion, three hundred thirty-five billion, two hundred forty-five million, five hundred thousand, one hundred thirty-three".