Base | Representation |
---|---|
bin | 1100001000001101101010… |
… | …0100100010111011100101 |
3 | 1202012211121012001110211102 |
4 | 3002003122210202323211 |
5 | 3221441040322001013 |
6 | 44210043251045445 |
7 | 2544303546341144 |
oct | 302033244427345 |
9 | 52184535043742 |
10 | 13335245500133 |
11 | 428149a4879a7 |
12 | 15b45628a0885 |
13 | 75967b83613b |
14 | 3416020db75b |
15 | 181d3121bd58 |
hex | c20da922ee5 |
13335245500133 has 2 divisors, whose sum is σ = 13335245500134. Its totient is φ = 13335245500132.
The previous prime is 13335245500121. The next prime is 13335245500163. The reversal of 13335245500133 is 33100554253331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12925340803489 + 409904696644 = 3595183^2 + 640238^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13335245500133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13335245500163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6667622750066 + 6667622750067.
It is an arithmetic number, because the mean of its divisors is an integer number (6667622750067).
Almost surely, 213335245500133 is an apocalyptic number.
It is an amenable number.
13335245500133 is a deficient number, since it is larger than the sum of its proper divisors (1).
13335245500133 is an equidigital number, since it uses as much as digits as its factorization.
13335245500133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243000, while the sum is 38.
Adding to 13335245500133 its reverse (33100554253331), we get a palindrome (46435799753464).
The spelling of 13335245500133 in words is "thirteen trillion, three hundred thirty-five billion, two hundred forty-five million, five hundred thousand, one hundred thirty-three".
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