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133384028433 = 344461342811
BaseRepresentation
bin111110000111001001…
…1101100000100010001
3110202021202120200221020
41330032103230010101
54141132302402213
6141135322350053
712431244351315
oct1741623540421
9422252520836
10133384028433
1151627896847
1221a2605b329
13c768cc7a16
146654ab9b45
153709eb3923
hex1f0e4ec111

133384028433 has 4 divisors (see below), whose sum is σ = 177845371248. Its totient is φ = 88922685620.

The previous prime is 133384028431. The next prime is 133384028473. The reversal of 133384028433 is 334820483331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133384028433 - 21 = 133384028431 is a prime.

It is not an unprimeable number, because it can be changed into a prime (133384028431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22230671403 + ... + 22230671408.

It is an arithmetic number, because the mean of its divisors is an integer number (44461342812).

Almost surely, 2133384028433 is an apocalyptic number.

It is an amenable number.

133384028433 is a deficient number, since it is larger than the sum of its proper divisors (44461342815).

133384028433 is an equidigital number, since it uses as much as digits as its factorization.

133384028433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44461342814.

The product of its (nonzero) digits is 497664, while the sum is 42.

The spelling of 133384028433 in words is "one hundred thirty-three billion, three hundred eighty-four million, twenty-eight thousand, four hundred thirty-three".

Divisors: 1 3 44461342811 133384028433