Base | Representation |
---|---|
bin | 10011011010011000110… |
… | …010110111100010100001 |
3 | 11201112021222121202110021 |
4 | 103122120302313202201 |
5 | 133324014323131111 |
6 | 2500455505033441 |
7 | 165243563146003 |
oct | 23323062674241 |
9 | 4645258552407 |
10 | 1334003333281 |
11 | 474825116823 |
12 | 196657025881 |
13 | 98a469aa1a8 |
14 | 487cd574373 |
15 | 24a79231d71 |
hex | 13698cb78a1 |
1334003333281 has 2 divisors, whose sum is σ = 1334003333282. Its totient is φ = 1334003333280.
The previous prime is 1334003333279. The next prime is 1334003333407. The reversal of 1334003333281 is 1823333004331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 802307152656 + 531696180625 = 895716^2 + 729175^2 .
It is a cyclic number.
It is not a de Polignac number, because 1334003333281 - 21 = 1334003333279 is a prime.
It is a super-4 number, since 4×13340033332814 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
Together with 1334003333279, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1334003333261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667001666640 + 667001666641.
It is an arithmetic number, because the mean of its divisors is an integer number (667001666641).
Almost surely, 21334003333281 is an apocalyptic number.
It is an amenable number.
1334003333281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334003333281 is an equidigital number, since it uses as much as digits as its factorization.
1334003333281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 34.
The spelling of 1334003333281 in words is "one trillion, three hundred thirty-four billion, three million, three hundred thirty-three thousand, two hundred eighty-one".
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