Base | Representation |
---|---|
bin | 111110000111101010… |
… | …0111011100011010111 |
3 | 110202022221202121112220 |
4 | 1330033110323203113 |
5 | 4141201142144343 |
6 | 141141133113423 |
7 | 12431542622553 |
oct | 1741724734327 |
9 | 422287677486 |
10 | 133401131223 |
11 | 51636508388 |
12 | 21a2b928873 |
13 | c76c705509 |
14 | 665708c863 |
15 | 370b741183 |
hex | 1f0f53b8d7 |
133401131223 has 16 divisors (see below), whose sum is σ = 183769313280. Its totient is φ = 86012305056.
The previous prime is 133401131221. The next prime is 133401131233. The reversal of 133401131223 is 322131104331.
It is not a de Polignac number, because 133401131223 - 21 = 133401131221 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133401131193 and 133401131202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133401131221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3579703 + ... + 3616776.
It is an arithmetic number, because the mean of its divisors is an integer number (11485582080).
Almost surely, 2133401131223 is an apocalyptic number.
133401131223 is a deficient number, since it is larger than the sum of its proper divisors (50368182057).
133401131223 is a wasteful number, since it uses less digits than its factorization.
133401131223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7196686.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 133401131223 its reverse (322131104331), we get a palindrome (455532235554).
The spelling of 133401131223 in words is "one hundred thirty-three billion, four hundred one million, one hundred thirty-one thousand, two hundred twenty-three".
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