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133401131223 = 3371677196479
BaseRepresentation
bin111110000111101010…
…0111011100011010111
3110202022221202121112220
41330033110323203113
54141201142144343
6141141133113423
712431542622553
oct1741724734327
9422287677486
10133401131223
1151636508388
1221a2b928873
13c76c705509
14665708c863
15370b741183
hex1f0f53b8d7

133401131223 has 16 divisors (see below), whose sum is σ = 183769313280. Its totient is φ = 86012305056.

The previous prime is 133401131221. The next prime is 133401131233. The reversal of 133401131223 is 322131104331.

It is not a de Polignac number, because 133401131223 - 21 = 133401131221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133401131193 and 133401131202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133401131221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3579703 + ... + 3616776.

It is an arithmetic number, because the mean of its divisors is an integer number (11485582080).

Almost surely, 2133401131223 is an apocalyptic number.

133401131223 is a deficient number, since it is larger than the sum of its proper divisors (50368182057).

133401131223 is a wasteful number, since it uses less digits than its factorization.

133401131223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7196686.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 133401131223 its reverse (322131104331), we get a palindrome (455532235554).

The spelling of 133401131223 in words is "one hundred thirty-three billion, four hundred one million, one hundred thirty-one thousand, two hundred twenty-three".

Divisors: 1 3 37 111 167 501 6179 18537 7196479 21589437 266269723 798809169 1201811993 3605435979 44467043741 133401131223