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13340212103 = 1710938318797
BaseRepresentation
bin11000110110010001…
…10111101110000111
31021102200221222201202
430123020313232013
5204310043241403
610043423013115
7651403634441
oct143310675607
937380858652
1013340212103
115726224889
12270373a19b
131347a0ba3a
14907a09491
15531255688
hex31b237b87

13340212103 has 16 divisors (see below), whose sum is σ = 14292495360. Its totient is φ = 12407164416.

The previous prime is 13340212099. The next prime is 13340212139. The reversal of 13340212103 is 30121204331.

It is a cyclic number.

It is not a de Polignac number, because 13340212103 - 22 = 13340212099 is a prime.

It is a super-2 number, since 2×133402121032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13340212163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 700301 + ... + 719097.

It is an arithmetic number, because the mean of its divisors is an integer number (893280960).

Almost surely, 213340212103 is an apocalyptic number.

13340212103 is a deficient number, since it is larger than the sum of its proper divisors (952283257).

13340212103 is a wasteful number, since it uses less digits than its factorization.

13340212103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19306.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13340212103 its reverse (30121204331), we get a palindrome (43461416434).

The spelling of 13340212103 in words is "thirteen billion, three hundred forty million, two hundred twelve thousand, one hundred three".

Divisors: 1 17 109 383 1853 6511 18797 41747 319549 709699 2048873 7199251 34830841 122387267 784718359 13340212103