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133402141333 is a prime number
BaseRepresentation
bin111110000111101100…
…0110010001010010101
3110202100000122221011101
41330033120302022111
54141201422010313
6141141210510101
712431554330516
oct1741730621225
9422300587141
10133402141333
115163703828a
1221a30135331
13c76c99a206
146657272a0d
15370b8905dd
hex1f0f632295

133402141333 has 2 divisors, whose sum is σ = 133402141334. Its totient is φ = 133402141332.

The previous prime is 133402141321. The next prime is 133402141339. The reversal of 133402141333 is 333141204331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133095821329 + 306320004 = 364823^2 + 17502^2 .

It is a cyclic number.

It is not a de Polignac number, because 133402141333 - 29 = 133402140821 is a prime.

It is a super-2 number, since 2×1334021413332 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133402141339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66701070666 + 66701070667.

It is an arithmetic number, because the mean of its divisors is an integer number (66701070667).

Almost surely, 2133402141333 is an apocalyptic number.

It is an amenable number.

133402141333 is a deficient number, since it is larger than the sum of its proper divisors (1).

133402141333 is an equidigital number, since it uses as much as digits as its factorization.

133402141333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 133402141333 its reverse (333141204331), we get a palindrome (466543345664).

The spelling of 133402141333 in words is "one hundred thirty-three billion, four hundred two million, one hundred forty-one thousand, three hundred thirty-three".