Base | Representation |
---|---|
bin | 100111110000011… |
… | …1000110111011001 |
3 | 10102222012022121011 |
4 | 1033200320313121 |
5 | 10213002142333 |
6 | 340212413521 |
7 | 45025665532 |
oct | 11740706731 |
9 | 3388168534 |
10 | 1334021593 |
11 | 625025193 |
12 | 3129172a1 |
13 | 1834ba5b8 |
14 | c9259689 |
15 | 7c1b09cd |
hex | 4f838dd9 |
1334021593 has 2 divisors, whose sum is σ = 1334021594. Its totient is φ = 1334021592.
The previous prime is 1334021581. The next prime is 1334021599. The reversal of 1334021593 is 3951204331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1175941264 + 158080329 = 34292^2 + 12573^2 .
It is a cyclic number.
It is not a de Polignac number, because 1334021593 - 25 = 1334021561 is a prime.
It is a super-2 number, since 2×13340215932 = 3559227221180515298, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1334021599) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667010796 + 667010797.
It is an arithmetic number, because the mean of its divisors is an integer number (667010797).
Almost surely, 21334021593 is an apocalyptic number.
It is an amenable number.
1334021593 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334021593 is an equidigital number, since it uses as much as digits as its factorization.
1334021593 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 31.
The square root of 1334021593 is about 36524.2603347419. The cubic root of 1334021593 is about 1100.8317656672.
The spelling of 1334021593 in words is "one billion, three hundred thirty-four million, twenty-one thousand, five hundred ninety-three".
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