Base | Representation |
---|---|
bin | 111110000111101111… |
… | …1111100101011000001 |
3 | 110202100011012100101011 |
4 | 1330033133330223001 |
5 | 4141202412110033 |
6 | 141141315040521 |
7 | 12431606312101 |
oct | 1741737745301 |
9 | 422304170334 |
10 | 133404019393 |
11 | 516381002a7 |
12 | 21a308a0141 |
13 | c7701a6ca8 |
14 | 6657601201 |
15 | 370bb11ccd |
hex | 1f0f7fcac1 |
133404019393 has 4 divisors (see below), whose sum is σ = 134779318660. Its totient is φ = 132028720128.
The previous prime is 133404019373. The next prime is 133404019417. The reversal of 133404019393 is 393910404331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 71391564864 + 62012454529 = 267192^2 + 249023^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133404019393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133404019373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 687649488 + ... + 687649681.
It is an arithmetic number, because the mean of its divisors is an integer number (33694829665).
Almost surely, 2133404019393 is an apocalyptic number.
It is an amenable number.
133404019393 is a deficient number, since it is larger than the sum of its proper divisors (1375299267).
133404019393 is an equidigital number, since it uses as much as digits as its factorization.
133404019393 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1375299266.
The product of its (nonzero) digits is 104976, while the sum is 40.
The spelling of 133404019393 in words is "one hundred thirty-three billion, four hundred four million, nineteen thousand, three hundred ninety-three".
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