Base | Representation |
---|---|
bin | 1100001000100000111001… |
… | …1111000010101111111011 |
3 | 1202020022221012200102021011 |
4 | 3002020032133002233323 |
5 | 3222032130312040443 |
6 | 44212300031054351 |
7 | 2544545555164525 |
oct | 302101637025773 |
9 | 52208835612234 |
10 | 13340411440123 |
11 | 4283700524099 |
12 | 15b55649713b7 |
13 | 759cc2b85071 |
14 | 341972236a15 |
15 | 182034a00b9d |
hex | c220e7c2bfb |
13340411440123 has 32 divisors (see below), whose sum is σ = 14082433643520. Its totient is φ = 12612763912320.
The previous prime is 13340411440079. The next prime is 13340411440133. The reversal of 13340411440123 is 32104411404331.
It is a cyclic number.
It is not a de Polignac number, because 13340411440123 - 221 = 13340409342971 is a prime.
It is a super-2 number, since 2×133404114401232 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13340411440133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 810811165 + ... + 810827617.
It is an arithmetic number, because the mean of its divisors is an integer number (440076051360).
Almost surely, 213340411440123 is an apocalyptic number.
13340411440123 is a deficient number, since it is larger than the sum of its proper divisors (742022203397).
13340411440123 is a wasteful number, since it uses less digits than its factorization.
13340411440123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17659.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13340411440123 its reverse (32104411404331), we get a palindrome (45444822844454).
The spelling of 13340411440123 in words is "thirteen trillion, three hundred forty billion, four hundred eleven million, four hundred forty thousand, one hundred twenty-three".
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