Base | Representation |
---|---|
bin | 111110000111110010… |
… | …0001110111010100101 |
3 | 110202100020022102020212 |
4 | 1330033210032322211 |
5 | 4141203204031233 |
6 | 141141355105205 |
7 | 12431622001034 |
oct | 1741744167245 |
9 | 422306272225 |
10 | 133405142693 |
11 | 516387a8249 |
12 | 21a31142205 |
13 | c7704ab374 |
14 | 665781471b |
15 | 370bc84a48 |
hex | 1f0f90eea5 |
133405142693 has 2 divisors, whose sum is σ = 133405142694. Its totient is φ = 133405142692.
The previous prime is 133405142623. The next prime is 133405142699. The reversal of 133405142693 is 396241504331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126588658849 + 6816483844 = 355793^2 + 82562^2 .
It is a cyclic number.
It is not a de Polignac number, because 133405142693 - 210 = 133405141669 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133405142693.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133405142699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66702571346 + 66702571347.
It is an arithmetic number, because the mean of its divisors is an integer number (66702571347).
Almost surely, 2133405142693 is an apocalyptic number.
It is an amenable number.
133405142693 is a deficient number, since it is larger than the sum of its proper divisors (1).
133405142693 is an equidigital number, since it uses as much as digits as its factorization.
133405142693 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 41.
The spelling of 133405142693 in words is "one hundred thirty-three billion, four hundred five million, one hundred forty-two thousand, six hundred ninety-three".
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