Base | Representation |
---|---|
bin | 11000110110010100… |
… | …01011011101101101 |
3 | 1021102201121102020222 |
4 | 30123022023131231 |
5 | 204310140230432 |
6 | 10043434221125 |
7 | 651406563461 |
oct | 143312133555 |
9 | 37381542228 |
10 | 13340555117 |
11 | 572643956a |
12 | 27038847a5 |
13 | 1347acbbc6 |
14 | 907a984a1 |
15 | 5312c2112 |
hex | 31b28b76d |
13340555117 has 2 divisors, whose sum is σ = 13340555118. Its totient is φ = 13340555116.
The previous prime is 13340555099. The next prime is 13340555131. The reversal of 13340555117 is 71155504331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11256997801 + 2083557316 = 106099^2 + 45646^2 .
It is a cyclic number.
It is not a de Polignac number, because 13340555117 - 220 = 13339506541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13340552117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670277558 + 6670277559.
It is an arithmetic number, because the mean of its divisors is an integer number (6670277559).
Almost surely, 213340555117 is an apocalyptic number.
It is an amenable number.
13340555117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340555117 is an equidigital number, since it uses as much as digits as its factorization.
13340555117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31500, while the sum is 35.
The spelling of 13340555117 in words is "thirteen billion, three hundred forty million, five hundred fifty-five thousand, one hundred seventeen".
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