Base | Representation |
---|---|
bin | 11000110110010101… |
… | …00011111000001001 |
3 | 1021102201210111102112 |
4 | 30123022203320021 |
5 | 204310201430423 |
6 | 10043440312105 |
7 | 651410461142 |
oct | 143312437011 |
9 | 37381714375 |
10 | 13340655113 |
11 | 57264a7705 |
12 | 2703912635 |
13 | 1347b35586 |
14 | 907ac2ac9 |
15 | 5312e1a78 |
hex | 31b2a3e09 |
13340655113 has 2 divisors, whose sum is σ = 13340655114. Its totient is φ = 13340655112.
The previous prime is 13340655077. The next prime is 13340655149. The reversal of 13340655113 is 31155604331.
It is a balanced prime because it is at equal distance from previous prime (13340655077) and next prime (13340655149).
It can be written as a sum of positive squares in only one way, i.e., 11056101904 + 2284553209 = 105148^2 + 47797^2 .
It is a cyclic number.
It is not a de Polignac number, because 13340655113 - 232 = 9045687817 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13340655113.
It is not a weakly prime, because it can be changed into another prime (13340651113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670327556 + 6670327557.
It is an arithmetic number, because the mean of its divisors is an integer number (6670327557).
Almost surely, 213340655113 is an apocalyptic number.
It is an amenable number.
13340655113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340655113 is an equidigital number, since it uses as much as digits as its factorization.
13340655113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 32.
The spelling of 13340655113 in words is "thirteen billion, three hundred forty million, six hundred fifty-five thousand, one hundred thirteen".
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