Base | Representation |
---|---|
bin | 10011011010011101000… |
… | …011011010111100110011 |
3 | 11201112110222001200222021 |
4 | 103122131003122330303 |
5 | 133324141121001431 |
6 | 2500510540252311 |
7 | 165245421353554 |
oct | 23323503327463 |
9 | 4645428050867 |
10 | 1334074781491 |
11 | 474861486931 |
12 | 196676b41097 |
13 | 98a58734c3a |
14 | 487d8c5232b |
15 | 24a80646b11 |
hex | 1369d0daf33 |
1334074781491 has 2 divisors, whose sum is σ = 1334074781492. Its totient is φ = 1334074781490.
The previous prime is 1334074781461. The next prime is 1334074781519. The reversal of 1334074781491 is 1941874704331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1334074781491 - 29 = 1334074780979 is a prime.
It is a super-2 number, since 2×13340747814912 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1334074781411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667037390745 + 667037390746.
It is an arithmetic number, because the mean of its divisors is an integer number (667037390746).
Almost surely, 21334074781491 is an apocalyptic number.
1334074781491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334074781491 is an equidigital number, since it uses as much as digits as its factorization.
1334074781491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2032128, while the sum is 52.
The spelling of 1334074781491 in words is "one trillion, three hundred thirty-four billion, seventy-four million, seven hundred eighty-one thousand, four hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •