133410021433 has 4 divisors (see below), whose sum is σ = 143672330788. Its totient is φ = 123147712080.

The previous prime is 133410021431. The next prime is 133410021487. The reversal of 133410021433 is 334120014331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 68391141289 + 65018880144 = 261517^2 + 254988^2 .

It is a cyclic number.

It is not a de Polignac number, because 133410021433 - 2¹ = 133410021431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133410021398 and 133410021407.

It is not an unprimeable number, because it can be changed into a prime (133410021431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5131154658 + ... + 5131154683.

It is an arithmetic number, because the mean of its divisors is an integer number (35918082697).

Almost surely, 2^133410021433 is an apocalyptic number.

133410021433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

133410021433 is a deficient number, since it is larger than the sum of its proper divisors (10262309355).

133410021433 is a wasteful number, since it uses less digits than its factorization.

133410021433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10262309354.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 133410021433 its reverse (334120014331), we get a palindrome (467530035764).

The spelling of 133410021433 in words is "one hundred thirty-three billion, four hundred ten million, twenty-one thousand, four hundred thirty-three".