Base | Representation |
---|---|
bin | 11000110110011000… |
… | …00010111011011111 |
3 | 1021102202112021111022 |
4 | 30123030002323133 |
5 | 204310301410242 |
6 | 10043452514355 |
7 | 651414002213 |
oct | 143314027337 |
9 | 37382467438 |
10 | 13341044447 |
11 | 5726743175 |
12 | 2703a7b9bb |
13 | 1347c40853 |
14 | 907b84943 |
15 | 53136c0d2 |
hex | 31b302edf |
13341044447 has 2 divisors, whose sum is σ = 13341044448. Its totient is φ = 13341044446.
The previous prime is 13341044441. The next prime is 13341044459. The reversal of 13341044447 is 74444014331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13341044447 - 26 = 13341044383 is a prime.
It is a super-3 number, since 3×133410444473 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13341044441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670522223 + 6670522224.
It is an arithmetic number, because the mean of its divisors is an integer number (6670522224).
Almost surely, 213341044447 is an apocalyptic number.
13341044447 is a deficient number, since it is larger than the sum of its proper divisors (1).
13341044447 is an equidigital number, since it uses as much as digits as its factorization.
13341044447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 13341044447 its reverse (74444014331), we get a palindrome (87785058778).
The spelling of 13341044447 in words is "thirteen billion, three hundred forty-one million, forty-four thousand, four hundred forty-seven".
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