133411244041 has 4 divisors (see below), whose sum is σ = 133412005012. Its totient is φ = 133410483072.

The previous prime is 133411244023. The next prime is 133411244059. The reversal of 133411244041 is 140442114331.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 140442114331 = 17 ⋅8261300843.

It is an interprime number because it is at equal distance from previous prime (133411244023) and next prime (133411244059).

It can be written as a sum of positive squares in 2 ways, for example, as 40251995641 + 93159248400 = 200629^2 + 305220^2 .

It is a cyclic number.

It is not a de Polignac number, because 133411244041 - 2⁵ = 133411244009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133411274041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30385 + ... + 517441.

It is an arithmetic number, because the mean of its divisors is an integer number (33353001253).

Almost surely, 2^133411244041 is an apocalyptic number.

It is an amenable number.

133411244041 is a deficient number, since it is larger than the sum of its proper divisors (760971).

133411244041 is an equidigital number, since it uses as much as digits as its factorization.

133411244041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 760970.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 133411244041 its reverse (140442114331), we get a palindrome (273853358372).

The spelling of 133411244041 in words is "one hundred thirty-three billion, four hundred eleven million, two hundred forty-four thousand, forty-one".