Base | Representation |
---|---|
bin | 111110001000000000… |
… | …0000101001111011001 |
3 | 110202100202001022112012 |
4 | 1330100000011033121 |
5 | 4141212041134342 |
6 | 141142215355305 |
7 | 12432041025023 |
oct | 1742000051731 |
9 | 422322038465 |
10 | 133412443097 |
11 | 5164193413a |
12 | 21a33682b35 |
13 | c771b6622b |
14 | 6658795013 |
15 | 370c727b82 |
hex | 1f100053d9 |
133412443097 has 2 divisors, whose sum is σ = 133412443098. Its totient is φ = 133412443096.
The previous prime is 133412443081. The next prime is 133412443103. The reversal of 133412443097 is 790344214331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75644801296 + 57767641801 = 275036^2 + 240349^2 .
It is a cyclic number.
It is not a de Polignac number, because 133412443097 - 24 = 133412443081 is a prime.
It is a super-2 number, since 2×1334124430972 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133412443007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706221548 + 66706221549.
It is an arithmetic number, because the mean of its divisors is an integer number (66706221549).
Almost surely, 2133412443097 is an apocalyptic number.
It is an amenable number.
133412443097 is a deficient number, since it is larger than the sum of its proper divisors (1).
133412443097 is an equidigital number, since it uses as much as digits as its factorization.
133412443097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 217728, while the sum is 41.
The spelling of 133412443097 in words is "one hundred thirty-three billion, four hundred twelve million, four hundred forty-three thousand, ninety-seven".
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