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133412443097 is a prime number
BaseRepresentation
bin111110001000000000…
…0000101001111011001
3110202100202001022112012
41330100000011033121
54141212041134342
6141142215355305
712432041025023
oct1742000051731
9422322038465
10133412443097
115164193413a
1221a33682b35
13c771b6622b
146658795013
15370c727b82
hex1f100053d9

133412443097 has 2 divisors, whose sum is σ = 133412443098. Its totient is φ = 133412443096.

The previous prime is 133412443081. The next prime is 133412443103. The reversal of 133412443097 is 790344214331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75644801296 + 57767641801 = 275036^2 + 240349^2 .

It is a cyclic number.

It is not a de Polignac number, because 133412443097 - 24 = 133412443081 is a prime.

It is a super-2 number, since 2×1334124430972 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133412443007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706221548 + 66706221549.

It is an arithmetic number, because the mean of its divisors is an integer number (66706221549).

Almost surely, 2133412443097 is an apocalyptic number.

It is an amenable number.

133412443097 is a deficient number, since it is larger than the sum of its proper divisors (1).

133412443097 is an equidigital number, since it uses as much as digits as its factorization.

133412443097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 217728, while the sum is 41.

The spelling of 133412443097 in words is "one hundred thirty-three billion, four hundred twelve million, four hundred forty-three thousand, ninety-seven".